EFGH is a rhombus. Show that EG bisects angle E and angle G both.
plz tell fast in hand written format becoz it is more easy to undertand that format
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EFGH is a rhombus. Show that EG bisects angle E and angle G both.
plz tell fast in hand written format becoz it is more easy to undertand that format
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Answer:
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Step-by-step explanation:
Consider two triangle ΔEGH and ΔEFG
Side EG is common side of both the triangle.
EF = FG = GH = HE
therefore all the sides are equal.
By SSS rules, these 2 triangles are congruent.
To prove EG bisects Angela E and Angele G both
Corresponding parts of congruent triangles are congruent.
Therefore <HEG = <GEF and <EGH = <EGF
so, EG bisects Angela E and Angele G both