Epand the following
1 (m+n) = m + __ + __
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Answer:
Step-by-step explanation:
1(m+n)=
m+n+0
Answer:
1+x) m (1−x) n =(1+mx+
2!m(m−1)x 2)(1−nx+ 2!n(n−1) x2 )=1+(m−n)x+[ 2n −mn+ 2(m 2 −m) ]x 2
Given m−n=3 or n=m−3
Hence
2n 2−n −mn+ 2m 2 −m =6
= 2(m−3)(m−4) −m(m−3)+ 2m 2−m
=−6⇒m 2 −7m+12−2m 2+6m+m 2 −m+12=0
⇒−2m+24=0⇒m=12.