equal moles of hydrogen and oxygen gases are placed in a container with a pinhole through which both can escape what fraction of oxygen escapes in the time required for one half of the hydrogen to escape
equal moles of hydrogen and oxygen gases are placed in a container with a pinhole through which both can escape what fraction of oxygen escapes in the time required for one half of the hydrogen to escape
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Answer:
By graham's law of diffusion
t2/t1 = (M2/M1) ^ ½ t2/t1
= (32/2) ^½ t2/t1
= (16/1) ^ ½ t2/t1
= 4t2 = 4t1
So 1 molecule of oxygen takes same time to escape as that of 4 molecules of Hydrogen
Time taken by X molecules of oxygen to escape in the same time required by ½ of hydrogen to escape = (½) x (¼) = 1/8