Evaluate integral tanx.dx..plss
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Step-by-step explanation:
dx
set
u = COs x.
then we find
du = - sin x dx
substitute du=-sin x, u=COs x
(integral) sin x
COs x dx = - (integral)
(-1) sin x dx
COs x
= - (integral) du
u
Solve the integral
= - ln |u| + C
substitute back u=COs x
= - ln |COs x| + C