Example 8.1 An object travels 16 m in 4 s
and then another 16 m in 2 s. What is
the average speed of the object?
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Example 8.1 An object travels 16 m in 4 s
and then another 16 m in 2 s. What is
the average speed of the object?
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Answer:
16 m/s
Explanation:
AVERAGE SPEED = TOTAL DISTANCE / TOTAL TIME TAKEN
THEREFORE,
16 + 16
_______ = 32 / 2 = 16 m/s
2 + 2
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Answer:
Given :-
To Find :-
Formula Used :-
[tex]\clubsuit[/tex] Average Speed Formula :
[tex]\mapsto \sf\boxed{\bold{\pink{Average\: Speed =\: \dfrac{Total\: Distance\: Travelled}{Total\: Time}}}}\\[/tex]
Solution :-
[tex]{\small{\bold{\purple{\underline{\leadsto\: In\: case\: of\: total\: distance\: travelled\: :-}}}}}[/tex]
Given :
Then,
[tex]\implies \sf Total\: distance\: travelled =\: d_1 + d_2[/tex]
[tex]\implies \sf Total\: distance\: travelled =\: 16 + 16[/tex]
[tex]\implies \sf\bold{\green{Total\: distance\: travelled =\: 32\: m}}[/tex]
[tex]{\small{\bold{\purple{\underline{\leadsto\: In\: case\: of\: total\: time\: taken\: :-}}}}}[/tex]
Given :
Then,
[tex]\implies \sf Total \: time\: taken =\: t_1 + t_2[/tex]
[tex]\implies \sf Total\: time\: taken =\: 4 + 2[/tex]
[tex]\implies \sf\bold{\green{Total\: time\: taken =\: 6\: seconds}}[/tex]
Now, we have to find the average speed of the object :
Given :
According to the question by using the formula we get,
[tex]\longrightarrow \sf Average\: Speed =\: \dfrac{\cancel{32}}{\cancel{6}}[/tex]
[tex]\longrightarrow \sf Average\: Speed =\: \dfrac{16}{3}[/tex]
[tex]\longrightarrow \sf\bold{\red{Average\: Speed =\: 5.33\: m/s}}[/tex]
[tex]\therefore[/tex] The average speed of the object is 5.33 m/s.