Factor completely!!! 4y2 + 25y + 6
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✔4y² + 25y + 6
➬4y² + (24+1)y + 6
➬4y² + 24y + y + 6
➬4y (y + 6) + 1 (y + 6)
➬(y + 6) (4y + 1)
✔y + 6 = 0 and 4y + 1 = 0
y = -6 and y = -1/4 (ans).
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Answer:
IT IS A QUADRATIC EQUATION SO MAXIMUM VALUE OF GIVEN VARIABLE OR MAXIMUM ROOT OR SOLUTION CAN BE 2.
SO VALUE OF ARE: