factories the following ײ-×-42
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Given:
Polynomial, p(x)=x²–x–42
Factorisation:
In p(x)=x²–x–42
Sum of zeroes=–1
Product of zeroes=–42
Such pair of integers=–7, +6
So,
p(x)=x²–7x+6x–42
or x(x–7)+6(x–7)
or (x+6)(x–7) which are the required factors
hope this help you alot