factorise 2n^2 - n - 45
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factorise 2n^2 - n - 45
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Answer:
Given, 2n² - n - 45=0
So, Multiplying 2 from n² with 45 to get 90 for getting our answer to be factorised.
2n²-10n+9n-45=0
2n(n-5)+9(n-5)=0
(2n+9) (n-5) =0
So, We have n= (-9/2 , 5)
Answer:
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