factorise 2x^2+y^2+8z^2-2√2xy+4√2yz-8xz
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factorise 2x^2+y^2+8z^2-2√2xy+4√2yz-8xz
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Answer:
-√2x=a, y=b, 2√2z=c
then give equation become
=a^2+b^2+c^2+2ab+2bc+2ca
and we know that a^2+b^2+c^2+2ab+2bc+2ca=(a+b+c) ^2
=(-√2x+y+2√2z) ^2