Factorise 4a2−9 please help
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4a² - 9
= (2a)² - (3)²
= (2a-3)(2a+3)
{ Since a² - b² = (a-b) (a+b) }
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4
[tex]4 {a}^{2?} - 9 \\ 4 {a}^{?2} + 6a - 6a - 9 \\ 2a ( 2a + 3) - 3(2a + 3) \\ (2a - 3)(2a + 3)[/tex]
is your answer