factorise 4p²q²(p+q)²-2pq(p+q)
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Answer:
(4p2+q2-r2)2-(2pq)2=(p2+q2-r2+2pq)(p2+q2-r2-2pq)
Step-by-step explanation:
Given:-
(4p2+q2-r2)2-4p2q2
Now,
This is forming an identity
a2-b2=(a+b)(a-b)
So,
here
a=(4p2+q2-r2)
b=(2pq)2
So,
(4p2+q2-r2)2-(2pq)2=(p2+q2-r2+2pq)(p2+q2-r2-2pq)
Step-by-step explanation:
2
q
2
(2p+q)
=p
2
q
2
×2p+p
2
q
2
×q
=2p
3
q
2
+p
2
q
3
Hence, the product of p
2
q
2
and 2p+q is equal to 2p
3
q
2
+p
2
q
3
.