factorise each of the following. 16x ^5 - 144 x ^ 3
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[tex] \huge \underbrace \mathrm \purple{Answer}[/tex]
16x5−144x3=16x3(x+3)(x−3)
Step-by-step explanation:
16x^{5}-144x^{3}16x5−144x3
=16x^{3}\times x^{2}-16x^{3}\times916x3×x2−16x3×9
=16x^{3}(x^{2}-9)16x3(x2−9)
= 16x^{3}(x^{2}-3^{2})16x3(x2−32)
=16x^{3}(x+3)(x-3)16x3(x+3)(x−3)
/* By algebraic identity:
\boxed {a^{2}-b^{2}=(a+b)(a-b)}a2−b2=(a+b)(a−b)
Therefore,
16x^{5}-144x^{3}=16x^{3}(x+3)(x-3)16x5−144x3=16x3(x+3)(x−3)
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