factorise (ii) 14(a – 3b)3 – 21p(a – 3b)
Share
factorise (ii) 14(a – 3b)3 – 21p(a – 3b)
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
14(a−3b)
3
−21p(a−3b)
Take out common in all terms,
Then,7(a−3b)[2(a−3b)
2
−3p]
Therefore, HCF of 14(a−3b)
3
and 21p(a−3b) is 7(a−3b).