Factorise the following
a^8-b^8
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Factor a^8-b^8
a8−b8a8-b8
Rewrite a8a8 as (a4)2(a4)2.
(a4)2−b8(a4)2-b8
Rewrite b8b8 as (b4)2(b4)2.
(a4)2−(b4)2(a4)2-(b4)2
Since both terms are perfect squares, factor using the difference of squaresformula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b)where a=a4a=a4 and b=b4b=b4.
(a4+b4)(a4−b4)