factorise the trinomial √2x²+7x+5√2
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factorise the trinomial √2x²+7x+5√2
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Answer:
√2x²+2x+5x+5√2
√2x(x+√2) + 5(x+√2)
(x+√2) (√2x+5)
Step-by-step explanation:
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[tex] \huge\colorbox{green}{answer}[/tex]
[tex] \sqrt{2} {x}^{2} + 7x + \sqrt[5]{2} = 0 \\ \\ \sqrt{2} {x}^{2} + 5x + \sqrt{2} x + \sqrt[5]{2} = 0 \\ \\ \sqrt{2} {x}^{2} + 5x + \sqrt{2} \times \sqrt{2} \times x + \sqrt[5]{2} = 0 \\ \\ x( \sqrt{2} + 5) + \sqrt{2} ( \sqrt{2} x + 5) = 0 \\ \\ ( \sqrt{2} + 5)(x + \sqrt{2} ) = 0 \\ \\ x = \frac{ - 5}{ \sqrt{2} } or \: - \sqrt{2} [/tex]