factorise this plzzzzz........
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Verified answer
Given : 4a^2 + b^2 + 25c^2 - 4ab - 10bc + 20ca
It can be written as:
= > 4a^2 + 10ac + 10ac - 2ab - 2ab + 25c^2 - 5bc - 5bc + b^2
= > 4a^2 + 10ac - 2ab + 10ac + 25c^2 - 5bc - 2ab - 5bc + b^2
= > 2a(2a + 5c - b) + 5c(2a + 5c - b) - b(2a + 5b - b)
= > (2a + 5c - b)(2a + 5b - c)
= > (2a + 5b - c)^2
Hope it helps!
Answer:
hope it hrlps you my friend