Factorise:-
x²- 1 - 2y - y²
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Answer:
Rearrange the terms as follows:
x^2 — y^2 — 2y — 1
Group the last three terms, factoring out a —1:
x^2 — (y^2 + 2y + 1)
Those last three terms are a perfect square:
x^2 — (y + 1)^2
Now you have the difference of two squares:
[x — (y + 1)][x + (y + 1)]
Remove the inner grouping symbols to get
(x — y — 1)(x + y + 1)
Answer:
I hope I helping
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