factorise x^3-13x-12 use factor theorem
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factorise x^3-13x-12 use factor theorem
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→ p( x ) = x³ - 13x - 12
=> p( -1 ) = ( -1 )³ - 13( -1 ) -12
=> p( -1 ) = -1 + 13 - 12 = 0
=> By Remainder / Factor theorem, ( x - [ -1 ] ) is a factor
=> p( x ) = ( x + 1 )( x² - x - 12 )
• p( -3 ) = ( -3 + 1 )( 9 - ( -3 ) - 12 ) = ( -2 )( 0 ) = 0
• p( 4 ) = ( 4 + 1 )( 16 - 4 - 12 ) = 5 x 0 = 0
=> p( x ) = ( x + 1 )( x + 3 )( x - 4 )
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