factorize
2k²-10k-12
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Answer:
(2k+4)(k-3)
Step-by-step explanation:
k= 6, k= -1
Step-by-step explanation:
2k²-10k-12
dividing the whole equation by 2 and hence it becomes:
k²-5k-6
k²-6k+1k-6
k(k-6)+1(k-6)
So, the roots are:
(k-6)=0 and (k+1)=0
k= 6 k= -1