FiIl in the blanks. P=9000 r =6(p.a.) n (years) =3 CI=1719.14 find the amount
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FiIl in the blanks. P=9000 r =6(p.a.) n (years) =3 CI=1719.14 find the amount
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Answer:
3£#369£73&94+6864)(you 2
Step-by-step explanation:
I am not sure but I am a little better than the other hand if you have any questions please let us know how to do
Given :
To Find :
Solution :
[tex]\Huge\sf\implies[/tex] [tex]{Amount \: = 9000\: × \: \left( 1 \: + \:\ frac {6}{100}\right)³ [/tex]
[tex]\Huge\sf\implies[/tex] [tex]{Amount \: = 9000\: × \: \frac{106}{100}\:\frac{106}{100}\:\frac{106}{100}[/tex]
[tex]\Huge\sf\implies[/tex] [tex]\boxed\color{green}{Amount\:=\:10719.144}[/tex]
[tex] \huge\sf\color{red} {More\: Information}[/tex]
Important formulae :
[tex] {Amount\:= \: principal\:+\:Interest}}}[/tex]
Interest = [tex]\frac{Principal×Rate×time}{100}[/tex]
Rate = [tex]\frac{Interest×100}{Principal×time}[/tex]
Time = [tex]\frac{Interest×100}{Principal×rate}[/tex]
[tex]\begin{gathered}\Large{\boxed{\begin{array}{cc}\\the \:amount\: of\: money\: lent\: or\\ borrowed \:is \:called \:the \:principal \\\The \:additional\: money \:charged\\ for\: its \:use \:is \:called\: Interest\:\\ If \:the\: interest \:due\: is \:added\\ to \:the\: principal\:,the\: total\: money\\ we\: receive \:or\: pay \:is \:called \:amount \:due \:at \:time\end{array}}}\end{gathered}[/tex]