Find : aplha⁴beta-beta⁴alpha , for x²+6x-2.
Without finding the zeros..
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Find : aplha⁴beta-beta⁴alpha , for x²+6x-2.
Without finding the zeros..
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Answer:
Let f(x) = 2x3 + x2 - 6x - 3 The zeros are - √(3) and √(3) Let the other zero be α = α ( - √(3)) (√(3)) = - ( - 3)2 = > - 3 α = 32 = >α = -12
Missing: aplha⁴beta- beta⁴alpha ,
Top answer
Let f(x) = 2x3 + x2 - 6x - 3 The zeros are - √(3) and √(3) Let the other zero be α = α ( - √(3)) (√(3)) = - ( - 3)2 = > - 3 α = 32 = >α = -12 More
Step-by-step explanation:
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Answer:
Let f(x) = 2x3 + x2 - 6x - 3 The zeros are - √(3) and √(3) Let the other zero be α = α ( - √(3)) (√(3)) = - ( - 3)2 = > - 3 α = 32 = >α = -12
Missing: aplha⁴beta- beta⁴alpha ,
Top answer
Let f(x) = 2x3 + x2 - 6x - 3 The zeros are - √(3) and √(3) Let the other zero be α = α ( - √(3)) (√(3)) = - ( - 3)2 = > - 3 α = 32 = >α = -12 More
Step-by-step explanation:
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