find hcf and lcm of 11008 and 7344
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Answer:
Step-by-step explanation:
11008 = 2^8 × 43
7344 = 2^4 × 7^2
Therefore, hcf = 2^4 = 16
Lcm = 2^8 × 43 × 7^2 = 539392
To find the LCM AND HCF OF 11008 and 7344 we have to find their prime factorization.
The prime factorization of 11008 is
2|11008
2|5504
2|2752
2|1376
2|688
2|344
2|172
2|86
43|43
1
11008=2*2*2*2*2*2*2*2*43
11008=2^8*43
The prime factorization of 7344 is
2|7344
2|3672
2|1836
2|918
3|459
3|153
3|51
17|17
1
7344=2*2*2*2*3*3*3*17
7344=2^4*3^3*17
Now, HCF=Product of the smallest power of each common
prime factor in the numbers.
HCF=2^4=16
LCM = Product of the greatest power of each prime factor,
involved in the numbers.
LCM=2^8*43*3^3*17=256*43*27*17=5052672