Find H.C.F of 144 ,180, 96.
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[tex]\underline{\textbf{Given:}}[/tex]
[tex]\textsf{144, 180, 96}[/tex]
[tex]\underline{\textbf{To find:}}[/tex]
[tex]\textsf{H.C.F of the given numbers}[/tex]
[tex]\underline{\textbf{Solution:}}[/tex]
[tex]\textsf{We find the HCF by prime factorization method}[/tex]
[tex]\mathsf{144=2^4{\times}3^2}[/tex]
[tex]\mathsf{180=2^2{\times}3^2{\times}5}[/tex]
[tex]\mathsf{96=2^5{\times}3}[/tex]
[tex]\textsf{Now we find out the common factors}[/tex]
[tex]\mathsf{144=\boxed{2}{\times}\boxed{2}{\times}2{\times}2{\times}\boxed{3}{\times}3}[/tex]
[tex]\mathsf{180=\boxed{2}{\times}\boxed{2}{\times}\boxed{3}{\times}3{\times}5}[/tex]
[tex]\mathsf{96=\boxed{2}{\times}\boxed{2}{\times}2{\times}2{\times}2{\times}\boxed{3}}[/tex]
[tex]\mathsf{H.C.F=2{\times}2{\times}3}[/tex]
[tex]\implies\boxed{\boxed{\mathsf{H.C.F=12}}}[/tex]
[tex]\underline{\textbf{Find more:}}[/tex]
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