find LCM and HCF of 105 and 438
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find LCM and HCF of 105 and 438
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Answer:
EXPLANATION.
cot∅ = 7/8.
As we know that,
cot∅ = 7/8 = Base/perpendicular.
\sf \implies \dfrac{(1 + sin \theta)(1 - sin \theta)}{(1 + cos \theta)(1 - cos \theta)}⟹
(1+cosθ)(1−cosθ)
(1+sinθ)(1−sinθ)
As we know that,
Formula of :
⇒ x² - y² = (x + y)(x - y).
Using this formula in equation, we get.
\sf \implies \dfrac{(1 - sin^{2} \theta)}{(1 - cos^{2} \theta)} = \dfrac{cos^{2} \theta}{sin^{2} \theta}⟹
(1−cos
2
θ)
(1−sin
2
θ)
=
sin
2
θ
cos
2
θ
⇒ cot²∅.
Put the value of cot∅ = 7/8 in equation, we get.
⇒ cot²∅ = (7/8)².
⇒ cot²∅ = 49/64.
MORE INFORMATION.
Fundamental trigonometric identities.
(1) = sin²∅ + cos²∅