Find p(0), p(-1), and p(+2) for the following polynomial.
p(b)=3b^2+b-1
whoever will give me the correct answer I will give thanks and I will follow them .
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Find p(0), p(-1), and p(+2) for the following polynomial.
p(b)=3b^2+b-1
whoever will give me the correct answer I will give thanks and I will follow them .
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Answer:
P(0)= -1 , P(-1)= 1 and P(2)= 13
Step-by-step explanation:
Firstly
P(0)= 3(0)²+0-1
= 0+0-1
=-1
Secondly
P(-1)= 3(-1)²+-1-1
= 3-2
=-1
Thirdly
P(2)= 3(2)²+2-1
= 12+1
=13