Find the additive inverse of 'x' in the given equation: √0.7744+√0.2305-x = 1.36
(1)-0.001
(2) 0.001
(3)-0.0001
(4) 0.0001
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Find the additive inverse of 'x' in the given equation: √0.7744+√0.2305-x = 1.36
(1)-0.001
(2) 0.001
(3)-0.0001
(4) 0.0001
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Answer:
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Step-by-step explanation:
[tex] \sqrt{0.7744} + \sqrt{0.2305} - x = 1.36[/tex]
[tex]0.88 + 0.48 - x = 1.36[/tex]
[tex]1.36 - 1.36 = x[/tex]
[tex]0 = x[/tex]
all the options are wrong answer will be -0 or 0