Find the angle which is twice of its supplement
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Let one supplement angle=x
Twice of supplement angle=2x
so we know two supplement angle =180°
Then
x+2x=180°
3x=180°
x=180÷3=60°
2×60=120°
hey buddy,
let the one supplement angel be x
and second one will be 2x
we know that,
sum of supplement angels = 180°
therefore,
x+2x = 180
3x = 180
x = 180÷3
x = 60
one supplement angel = x = 60°
and the second one = 2x =2*60 = 120°
hope it helps you
thank you