find the area of 4 walls and the floor of a rectangular room
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Let l, b, h be the lengths of AB,AD and AE as shown in the figure. Here l and b are the length and breadth of the floor and h the height of the room.
For the rectangle ABFE, the lengths of two adjacent sides are l and h. its area = lh
For the rectangle BCGF, the lengths of two adjacent sides are b and h. its area = bh
For the rectangle CDHG, the lengths of two adjacent sides are l and h. its area = lh
For the rectangle DAEH, the lengths of two adjacent sides are b and h. its area = bh
Observe the opposite walls being of the same size and shape have the same area too.
Hence the total area of the four walls = lh+bh+lh+bh
= 2lh+2bh
= 2h(l+b)
Solution of the question = 2(lb + bh + lh) - lb = 2bh + 2lh + lb