find the area of a triangle, two sides of which are 8cm and 11cm and the perimeter is 32 cm..
answerrrrrr please
thanks lots of heartssss
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find the area of a triangle, two sides of which are 8cm and 11cm and the perimeter is 32 cm..
answerrrrrr please
thanks lots of heartssss
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peimeter=32 cm.
sides=8,11
=sum of both sides - perimetre
32-8+11
32-19=13
sides=8 cm., 11 cm., 13 cm.
semi perimeter =a+ b+ c / 2
= 8+11+13 /2
32/2
so, s=16 cm.
area of a triangle = [root under] s(s-a) (s-b) (s-c)
s-a=16-8=8
s-b=16-11=5
s-c=16-13=3
[root under] 16 x 8 x 5 x 3
[root under] 2 x 8 x 8 x 5 x 3
=8 [root under] 30
=1/2 INTO 8 INTO 11
=4 INTO 11
AREA OF THE TRIANGLE=44CM^2