Find the area of an isosceles triangle whose length is 16cmand one of its equal side is 10cm.
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Find the area of an isosceles triangle whose length is 16cmand one of its equal side is 10cm.
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Base = 16cm
Let's use herons formula to find the area.
Area = √s (s - a) (s - b) (s - c)
Where,
a = 10cm
b = 10cm
c = 16cm
To find s:-
s = a+b+c/2
s = 10 + 10 + 16/2
s = 36/2
s = 18
Area = √s (s - a) (s - b) (s - c)
Area = √18 (18 - 10) (18 - 10) (18 - 16)
Area = √18 × 8 × 8 × 2
Area = √3 × 3 × 2 × 8 × 8 × 2
Area = 3 × 2 × 8
Area = 48cm^2
.Equal sides of the isosceles triangle = 10cm
Base = 16cm
Let's use herons formula to find the area.
Area = √s (s - a) (s - b) (s - c)
Where,
a = 10cm
b = 10cm
c = 16cm
To find s:-
s = a+b+c/2
s = 10 + 10 + 16/2
s = 36/2
s = 18
Area = √s (s - a) (s - b) (s - c)
Area = √18 (18 - 10) (18 - 10) (18 - 16)
Area = √18 × 8 × 8 × 2
Area = √3 × 3 × 2 × 8 × 8 × 2
Area = 3 × 2 × 8
Area = 48cm^2