find the area of following polygon
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Find the length of AL, LM, MN, NO, OD, ND so that it may be easy.
In Δ ALB, area = 1/2 bh = 1/2 * 10 cm * 30 cm = 150 cm²
In Δ AMF, area = 1/2 bh = 1/2 * 20 * 20 = 200 cm²
In Δ EOD, area = 1/2 bh = 1/2 * OD * EO = 1/2 * 30 * 60 = 900 cm²
In Δ CND, area = 1/2 bh = 1/2 * CN * ND = 1/2 * 40 * 40 = 800 cm²
Now, in trapezium CBLN,
height = 40 cm, both sides are 30 and 40 cm
area = 1/2 h (sum of both sides)
1/2 * 40 * (30 + 40)
1/2 * 40 * 70 = 1400 cm²
Similarly to find area of trape. EFMN ,
1/2 * 30 * 80 = 1200cm²
Now, adding all these areas, we get :
(150 + 200 + 800 + 900 + 1400 + 1200)cm² = 4650 cm²
Hence area of the polygon is 4650 cm². I have not written some steps. Hope it may understand.