find the area of rhobus whose diagonals are of length 15 cm and 9.1 cm
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find the area of rhobus whose diagonals are of length 15 cm and 9.1 cm
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Answer:
68.25 cm²
Step-by-step explanation:
LET THE DIAGONALS BE d1 and d2
AREA OF THE RHOMBUS=
[tex] \frac{d1 \times d2}{2} [/tex]
=
[tex] \frac{15 \times 9.1}{2} [/tex]
=68.25 cm²
Answer:
Area of the rhombus=d1×d2/2
=15×9.1/2
=68.25cm²
Step-by-step explanation:
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