Find the area of right angled triangle whose sides forming an right angle are 13cm and 9 cm
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Find the area of right angled triangle whose sides forming an right angle are 13cm and 9 cm
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Three ways of doing it :
According to pythogaras theorem,
5² + 12² = 13²
=> 5 & 12 or 12 & 5 is the base and altitude of the triangle respectively.
=> Area = ½ x base x altitude
= ½ x 5 x 12 = 30 cm²
Use Heron’s Formula
A = √{s(s - a)(s - b)(s - c)} where s = (a+b+c)/2
=> s = (5+12+13)/2 = 15
Area = √(15x 10 x 3 x 2) = √900 = 30 cm²
Use sin formula
Area = ½ x a x b x sin (theta)
=> ½ x 5 x 12 x Sin 90°
= 30 x Sin 90° = 30 x 1 = 30 cm²
The formula for the area of a triangle is bh/2
(half base×height)
(12*5)2 = 30cm²
Answer:
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