find the area of right angled triangle with length of sides containing the right angle as 8cm and 10cm .
find the area of right angled triangle with length of sides containing the right angle as 8cm and 10cm .
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Answer:
By pythagoras theorem:-
8^2+10^2=(Hypotenuse)^2
64+100=(Hypotenuse)^2
164=(Hypotenuse)^2
root164=Hypotenuse
12.8=Hypotenuse
Area of right angled triangle=1/2(Base×Height)
=1/2(8×10)
=1/2×80
=40cm^2