find the area of the rhombus
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Answer:
Let the length of other diagonal be a.
As we know diagonals of any rhombus bisect each other at 90°.
In any of the formed right angled triangle, applying Pythagoras theorem,
→ ( 1/2 of 6 )² + ( 1/2 of a )² = 5²
→ 3² + ( 1/2 of a )² = 5²
→ ( 1/2 of a )² = 5² - 3² = 25 - 9
→ ( 1/2 of a )² = 16
→ ( 1/2 of a ) = 4
We know,
Area of rhombus is half of the product of diagonals here,
Area = (1/2)(a)(6)
= 4*6
= 24 cm²
Hence, area of the rhombus is 24 cm².
Given:-
Length = 5 cm
diagonals = 6cm
To Find:-
Area of the rhombus
Calculations:-
Let the length of other diagonal be a. Diagonals of rhombus bisects each other at 90°.
NoW,
Applying Pythagoras formula,
➡ (1/2 of 6) ^2 +( 1/2 of a) ^2 = 5^2
➡ 3^2 +(1/2 of a^2) = 5^2
➡ (1/2 of a^2 ) = 5^2 - 3^2 = 25 - 9
➡ (1/2 of a^2) = 16
➡ (1/2 of a) = 4
We knoW,
Area of rhombus is half of the products of the diagonal ,here
Area = (1/2)(a)(6)
➡ 4*6
➡ [tex]{\tt{24 cm^2}}[/tex]
[tex]{\tt {24 cm^2}}[/tex]will be the area of rhombus if the length of its side is 5 cm and it's diagonal will be 6 cm.