find the area of the shaded region
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Answer:
refer to the attachment
Answer:
cd=24 then
dq=12
dp²=pq²+dq²
=(12)²+(5)²
=144+25
=169
dp=13
ar(dpq)=1/2×12×5
=30
dpq=cpq
cpd=dpq+cpq
=30+30
=60
ar(abcd)=(ab+cd)×rb/2
=(24+18)×10/2
=42×5
=210
ar(abcd)+ar(dpc)=210+30=240