find the area of trapezium whose parallel sides of length 10m and 15cm are at a distance of 6 cm from each other, calculate this area as a :-
i)The sum of the areas of two triangles and one rectangle. (with figure)
ii)the difference of the area of the rectangle and the sum of the areas of two triangles. (with figure)
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Answer:
area of trapezium = 1/2×(a+b) d
1/2(10+15)6
1/2×25×6
= 75 cm ²