find the average of first n natural numbers
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find the average of first n natural numbers
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Answer:
hy mate here is ur answer
Step-by-step explanation:
The average of first n natural numbers = (n+1)/2. The average of squares of first n natural numbers = (n+1)(2n+1)/6. The average of cubes of first n natural numbers = n(n+1)2/4. The average of odd numbers from 1 to n = (last odd number+1)/2.
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