Find the circumference of a circle whose diameter is : (2) 10.5 m (3) 40.6 m (1) 7 m
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Find the circumference of a circle whose diameter is : (2) 10.5 m (3) 40.6 m (1) 7 m
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Answer:
10.5 m is right ans
Step-by-step explanation:
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Step-by-step explanation:
According to the Question
We have to calculate the circumference of a circle whose diameter are given
(2) 10.5 m
Radius = 10.5/2
Radius = 5.25m
On substituting the value we get
↠ Circumference = 2 × 3.14 × 5.25
↠ Circumference = 6.28 × 5.25
↠ Circumference = 32.97 m
(3) 40.6 m
Radius = 40.6/2
Radius = 20.3m
On substituting the value we get
↠ Circumference = 2 × 3.14 × 20.3
↠ Circumference = 6.28 × 20.3
↠ Circumference = 127.484
(4) 7m
Radius = 7/2
Radius = 3.5
On substituting the value we get
↠ Circumference = 2×3.14 × 3.5
↠ Circumference = 6.28 × 3.5
↠ Circumference = 21.98m
Additional Information !!
[tex]\begin{gathered}\boxed{\begin {array}{cc}\\ \quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}[/tex]