find the coffiecient of x^2 and x in the expansions (x-3) (x+7) (x-8)
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find the coffiecient of x^2 and x in the expansions (x-3) (x+7) (x-8)
explain it step by step
Explain it step by step
Explain it step by step
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Answer:
(x-3) (x+7) (x-8) = 0 (given expansion)
(x^2+7x-3x-21) (x-8)=0 (distributive property applied
for (x-3) and (x+7))
x^3-8x^2+7x^2-56x-3x^2+24x-21x+168=0
(distributive property for the
rest)
x^3-4x^2-53x+168=0
coeffecient of x^2 = -4
coeffiefient of x = -53