Find the complement of the following Boolean function and reduce to a minimum number of literals.
B’D + A’BC’ + ACD + A’BC
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Find the complement of the following Boolean function and reduce to a minimum number of literals.
B’D + A’BC’ + ACD + A’BC
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Answer:
B'D+A'BC'+A'BC+ACD
=B'D+A'B+ACD
So (B'D+A'B+ACD)'
=(B'D+A'B)'.(ACD)'
=((B'D)' . (A'B)'). (A'+(CD)')
=(B+D').(A+B').(A'+C'+D')
=(BA+D'A+D'B').(A'+C'+D')
=BAC'+BAD'+D'AC'+D'A+D'B'A'+D'B'C'+D'B'
=BAC'+BAD'+D'AC'+D'A+D'B'
=ABC'+AD'+D'B'
Explanation:
Answer:
thanku for helping
Explanation:
thanku , thanku very much