find the coordinates of the points where y-axis cut the line 3x-y=4 .
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find the coordinates of the points where y-axis cut the line 3x-y=4 .
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Answer:
Step-by-step explanation:
Let the point be (x,y) as it lies on 3x+y+4=0
⇒y=−3x−4
⇒ Point =(x,−3x−4)
Distance of this is equidistant from (−5,6) and (3,2)
⇒(x+5)2+(6+3x+4)2
=(x−3)2+(2+3x+4)2
⇒(x+5)2+(3x+10)2=(x−3)2+(3x+6)2
⇒x2+25+10x+9x2+100+60x=x2+9−6x+9x2+36−36x
⇒70x+125=30x+45
⇒40x=−80
⇒x=−2
⇒y=−3(−2)−4=2
⇒ Point =(−2,2)