Find the cubes root of the following numbers the by using prime factorisation .i) 27
pls help
Share
Find the cubes root of the following numbers the by using prime factorisation .i) 27
pls help
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
Cube root of 27 is 3
As 3×3×3=27
[tex]{\huge{\boxed{\mathcal{\red{Answer}}}}}[/tex]
The value of the cube root of 27 is 3. It is the real solution of the equation x³ = 27.
Cube root of 27 in radical form: ∛27.
[tex] \: \: \: \: \: \: \sqrt[3]{27} \: \: \: \: \: \: = \: \: \sqrt[3]{ ( 3 × 3 × 3 )} [/tex]
[tex]\huge\ = \: \: \: \: \: \: \: \: 3[/tex]
Hope It'll Helps!