Find the current drawn from the battery by the network resistors shown in fig.
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Find the current drawn from the battery by the network resistors shown in fig.
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Explanation:
Equivalent resistance the given network is
R
1
=
R
4
1
+
R
1
+R
2
+R
3
1
=
10
1
+
10+10+10
1
=
10
1
+
30
1
=
30
3+1
=
30
4
∴ R=
4
30
=7.5 Ω
Current drawn from the battery
I=
R
V
=
7.5
3
=
75
30
=
5
2
⇒ I=0.4 A
Answer:
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