Find the distance the point p(3,4) and the origin.
simple question
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Find the distance the point p(3,4) and the origin.simple question
Find the distance the point p(3,4) and the origin.
simple question
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[tex]\textbf{Given:}[/tex]
[tex]\textsf{Points are (3,4) and (0,0)}[/tex]
[tex]\textbf{To find:}[/tex]
[tex]\textsf{The distance between (3,4) and (0,0)}[/tex]
[tex]\textbf{Solution:}[/tex]
[tex]\textbf{Formula used:}[/tex]
[tex]\boxed{\begin{minipage}{7cm}$\underline{\textsf{Distance formula:}}\\\\\mathsf{The\;distance\;between\;(x_1,y_1)\;and\;(x_2,y_2)\;is}\\\\\mathsf{d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}$\end{minipage}}[/tex]
[tex]\textsf{By using distance formula,}[/tex]
[tex]\textsf{The distance between (3,4) and (0,0)}[/tex]
[tex]\mathsf{=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}[/tex]
[tex]\mathsf{=\sqrt{(3-0)^2+(4-0)^2}}[/tex]
[tex]\mathsf{=\sqrt{3^2+4^2}}[/tex]
[tex]\mathsf{=\sqrt{9+16}}[/tex]
[tex]\mathsf{=\sqrt{25}}[/tex]
[tex]\mathsf{=5\;units}[/tex]
[tex]\therefore\textsf{The distance between (3,4) and (0,0) is 5 units}[/tex]
[tex]\textbf{Find more:}[/tex]
The distance between the points P(-6 , 7) and Q(-1 , -5) is- * 1 point 14 units 12 units 13 units 11 units
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Find all possible values of x for which the distance between the points A ( X , - 1) and B ( 5 , 3) is 5 units
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