Find the effective resistance in the given
Circut.
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Answer:
Explanation:
Effective resistance (Ef) in parallel circuit
1/Ef = 1/3 + 1/6
Ef = 2 ohm
Now, 2 ohm and 6 ohm are in seies combination,
So total effective resistance = 2 + 6 ohm
= 8 ohm
Answer:
R = 11Ω
Explanation:
firstly , 3Ω & 6Ω are in parallel
so , there equivalent resistance
=> 1/R' = (1/3) + (1/6) = { (1×2) + (1×1) } ÷ 6
=> 1/R' = (3/6) = (1/2)
=> R' = 2Ω
not equivalent resistance of whole circuit is ,series combination of R' & 9Ω resistor
therefore
R = (2) + (9)
R = 11Ω