find the equation of circle with centre(-3,2) and radius 5.
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find the equation of circle with centre(-3,2) and radius 5.
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Answer:
x^2+y^2+6x-4y=12
Step-by-step explanation:
As we know,
(x-h)^2+(y-k)^2=r^2
Given,
centre - (-3,2) = (h,k)
radius-5 units
Now as per question,
(x+3)^2+(y-2)^2=5^2
x^2+9+6x+y^2+4-4y=25
x^2+y^2+6x-4y+13=25
x^2+y^2+6x-4y=12