Find the equation of the circle whose centre lies on the negative direction of y-axis at a
distance 3 units from origin and whose radius is 4 units.
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Find the equation of the circle whose centre lies on the negative direction of y-axis at a
distance 3 units from origin and whose radius is 4 units.
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A/q
ln negative direction
distance will be= -3(on y-axis side)
radius=4(given)
then,
Central form=(x-h)2+(y-k)2=r2
(x-0)2+{(y-(-3)}2=(4)2
X2+Y2+6y-7=0. ( this is the equation that we needed)
HOPE IT WILL HELP YOU
Answer:
x2 + y2 = r2 , and this is the equation of a circle of radius r whose centre is the origin O(0, 0). The equation of a circle of radius r and centre the origin is x2 + y2 = r2 .
Step-by-step explanation:
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