Find the equivalent resistance of the following figures.
Give your answer with detailed explanation. (necessary steps)
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Find the equivalent resistance of the following figures.
Give your answer with detailed explanation. (necessary steps)
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Answer:
[tex]\huge\boxed{Answer}[/tex]
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a) Figure 'a ' is type of parallel connection
Formula =
[tex] \frac{1}{r1 } + \frac{1}{r2} \\ = \frac{1}{2} + \frac{1}{2} = \frac{2}{2} ohm = 1ohm [/tex]
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c) Figure 'c' is also parallel connection
Formula =
[tex] \frac{1}{r1 } + \frac{1}{r2} \\ = \frac{1}{1} + \frac{1}{1} = \frac{2}{1} \\ = \frac{1}{2} ohm \\ \: \: \: \: \: [/tex]
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b) Figure 'b' is also parallel connection
Formula =
By applying parallel's formula
We'll get the answer 1/R = 5/2
==> R = 2/5 ohm
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d) Figure ' d' is both parallel & series connection
Using parallel's formula
Formula = 1/R1 +1/R2 =1/1 +1/1 = 2/1
==> R = 1/2 ****
1/R1 + 1 R2 = 1/1+ 1/1 = 2/1
==> R=1/2***
Applying series's formula
=R1+R2= 1/2+1/2 = 2/2ohm
= 1 ohm
^❤^ Hope this'll help U Loveen
Answer:
Explanation:
(a) is parallel.. so resistance is 1/Rn= 1/2 +1/2
Rn=1 ohm
(b)Same way as (a)
(c) Same way as (a)
(d) looks complicated but if we redraw the diagram(don't keep circuits in diamond shape),it will be easier to solve
1/Rn=1/2+1/2(as add series and then parallel)
Rn=1 ohm