Find the general solution of 2cos^2x − 3sinx = 0
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Answer:
POSSIBLE VALUES FOR sin x = 2 , 1/2
2cos 2 x + 3sinx=0
⇒2(1−sin 2 x)+3sinx=0
⇒2(sin 2 x)−3sinx−2=0
⇒2(sin 2 x)−4sinx+sinx−2=0
⇒2sinx(sinx−2)+(sinx−2)=0
⇒(sinx−2)+(2sinx+1)=0
⇒sin x=2,sin x=− 1/2
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pihu
class 8
age 13
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